Integrand size = 16, antiderivative size = 59 \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\frac {2 \sqrt {e} q \arctan \left (\frac {\sqrt {d} (f+g x)}{\sqrt {e}}\right )}{\sqrt {d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )}{g} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2533, 2498, 269, 211} \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\frac {2 \sqrt {e} q \arctan \left (\frac {\sqrt {d} (f+g x)}{\sqrt {e}}\right )}{\sqrt {d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )}{g} \]
[In]
[Out]
Rule 211
Rule 269
Rule 2498
Rule 2533
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \log \left (c \left (d+\frac {e}{x^2}\right )^q\right ) \, dx,x,f+g x\right )}{g} \\ & = \frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )}{g}+\frac {(2 e q) \text {Subst}\left (\int \frac {1}{\left (d+\frac {e}{x^2}\right ) x^2} \, dx,x,f+g x\right )}{g} \\ & = \frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )}{g}+\frac {(2 e q) \text {Subst}\left (\int \frac {1}{e+d x^2} \, dx,x,f+g x\right )}{g} \\ & = \frac {2 \sqrt {e} q \tan ^{-1}\left (\frac {\sqrt {d} (f+g x)}{\sqrt {e}}\right )}{\sqrt {d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )}{g} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.34 \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\frac {\frac {2 \sqrt {e} q \arctan \left (\frac {\sqrt {d} (f+g x)}{\sqrt {e}}\right )}{\sqrt {d}}-2 f q \log (f+g x)+g x \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right )+f q \log \left (e+d (f+g x)^2\right )}{g} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(110\) vs. \(2(51)=102\).
Time = 0.93 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.88
method | result | size |
parts | \(\ln \left (c \left (d +\frac {e}{\left (g x +f \right )^{2}}\right )^{q}\right ) x +2 q e g \left (-\frac {f \ln \left (g x +f \right )}{g^{2} e}+\frac {\frac {f \ln \left (d \,g^{2} x^{2}+2 d f g x +d \,f^{2}+e \right )}{2 g}+\frac {e \arctan \left (\frac {2 d \,g^{2} x +2 d f g}{2 \sqrt {d e}\, g}\right )}{\sqrt {d e}\, g}}{e g}\right )\) | \(111\) |
default | \(\ln \left (c \left (\frac {d \,g^{2} x^{2}+2 d f g x +d \,f^{2}+e}{\left (g x +f \right )^{2}}\right )^{q}\right ) x +2 q e g \left (-\frac {f \ln \left (g x +f \right )}{g^{2} e}+\frac {\frac {f \ln \left (d \,g^{2} x^{2}+2 d f g x +d \,f^{2}+e \right )}{2 g}+\frac {e \arctan \left (\frac {2 d \,g^{2} x +2 d f g}{2 \sqrt {d e}\, g}\right )}{\sqrt {d e}\, g}}{e g}\right )\) | \(129\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 120 vs. \(2 (51) = 102\).
Time = 0.34 (sec) , antiderivative size = 287, normalized size of antiderivative = 4.86 \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\left [\frac {g q x \log \left (\frac {d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e}{g^{2} x^{2} + 2 \, f g x + f^{2}}\right ) + f q \log \left (d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e\right ) - 2 \, f q \log \left (g x + f\right ) + g x \log \left (c\right ) + q \sqrt {-\frac {e}{d}} \log \left (\frac {d g^{2} x^{2} + 2 \, d f g x + d f^{2} + 2 \, {\left (d g x + d f\right )} \sqrt {-\frac {e}{d}} - e}{d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e}\right )}{g}, \frac {g q x \log \left (\frac {d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e}{g^{2} x^{2} + 2 \, f g x + f^{2}}\right ) + f q \log \left (d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e\right ) - 2 \, f q \log \left (g x + f\right ) + g x \log \left (c\right ) + 2 \, q \sqrt {\frac {e}{d}} \arctan \left (\frac {{\left (d g x + d f\right )} \sqrt {\frac {e}{d}}}{e}\right )}{g}\right ] \]
[In]
[Out]
Timed out. \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\text {Timed out} \]
[In]
[Out]
Exception generated. \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=\text {Exception raised: ValueError} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 139 vs. \(2 (51) = 102\).
Time = 0.53 (sec) , antiderivative size = 139, normalized size of antiderivative = 2.36 \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=d e g^{4} q {\left (\frac {f \log \left (d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e\right )}{d e g^{5}} - \frac {2 \, f \log \left ({\left | g x + f \right |}\right )}{d e g^{5}} + \frac {2 \, \arctan \left (\frac {d g x + d f}{\sqrt {d e}}\right )}{\sqrt {d e} d g^{5}}\right )} + q x \log \left (d g^{2} x^{2} + 2 \, d f g x + d f^{2} + e\right ) - q x \log \left (g^{2} x^{2} + 2 \, f g x + f^{2}\right ) + x \log \left (c\right ) \]
[In]
[Out]
Time = 1.85 (sec) , antiderivative size = 163, normalized size of antiderivative = 2.76 \[ \int \log \left (c \left (d+\frac {e}{(f+g x)^2}\right )^q\right ) \, dx=x\,\ln \left (c\,{\left (d+\frac {e}{{\left (f+g\,x\right )}^2}\right )}^q\right )-\frac {2\,f\,q\,\ln \left (f+g\,x\right )}{g}+\frac {\ln \left (e\,\sqrt {-d\,e}-3\,d\,f^2\,\sqrt {-d\,e}+4\,d\,e\,f+d\,e\,g\,x-3\,d\,f\,g\,x\,\sqrt {-d\,e}\right )\,\left (q\,\sqrt {-d\,e}+d\,f\,q\right )}{d\,g}-\frac {\ln \left (3\,d\,f^2\,\sqrt {-d\,e}-e\,\sqrt {-d\,e}+4\,d\,e\,f+d\,e\,g\,x+3\,d\,f\,g\,x\,\sqrt {-d\,e}\right )\,\left (q\,\sqrt {-d\,e}-d\,f\,q\right )}{d\,g} \]
[In]
[Out]